Integrand size = 22, antiderivative size = 166 \[ \int \frac {x^4 \arctan (a x)^2}{c+a^2 c x^2} \, dx=\frac {x}{3 a^4 c}-\frac {\arctan (a x)}{3 a^5 c}-\frac {x^2 \arctan (a x)}{3 a^3 c}-\frac {4 i \arctan (a x)^2}{3 a^5 c}-\frac {x \arctan (a x)^2}{a^4 c}+\frac {x^3 \arctan (a x)^2}{3 a^2 c}+\frac {\arctan (a x)^3}{3 a^5 c}-\frac {8 \arctan (a x) \log \left (\frac {2}{1+i a x}\right )}{3 a^5 c}-\frac {4 i \operatorname {PolyLog}\left (2,1-\frac {2}{1+i a x}\right )}{3 a^5 c} \]
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Time = 0.28 (sec) , antiderivative size = 166, normalized size of antiderivative = 1.00, number of steps used = 17, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.455, Rules used = {5036, 4946, 327, 209, 5040, 4964, 2449, 2352, 4930, 5004} \[ \int \frac {x^4 \arctan (a x)^2}{c+a^2 c x^2} \, dx=\frac {\arctan (a x)^3}{3 a^5 c}-\frac {4 i \arctan (a x)^2}{3 a^5 c}-\frac {\arctan (a x)}{3 a^5 c}-\frac {8 \arctan (a x) \log \left (\frac {2}{1+i a x}\right )}{3 a^5 c}-\frac {4 i \operatorname {PolyLog}\left (2,1-\frac {2}{i a x+1}\right )}{3 a^5 c}-\frac {x \arctan (a x)^2}{a^4 c}+\frac {x}{3 a^4 c}-\frac {x^2 \arctan (a x)}{3 a^3 c}+\frac {x^3 \arctan (a x)^2}{3 a^2 c} \]
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Rule 209
Rule 327
Rule 2352
Rule 2449
Rule 4930
Rule 4946
Rule 4964
Rule 5004
Rule 5036
Rule 5040
Rubi steps \begin{align*} \text {integral}& = -\frac {\int \frac {x^2 \arctan (a x)^2}{c+a^2 c x^2} \, dx}{a^2}+\frac {\int x^2 \arctan (a x)^2 \, dx}{a^2 c} \\ & = \frac {x^3 \arctan (a x)^2}{3 a^2 c}+\frac {\int \frac {\arctan (a x)^2}{c+a^2 c x^2} \, dx}{a^4}-\frac {\int \arctan (a x)^2 \, dx}{a^4 c}-\frac {2 \int \frac {x^3 \arctan (a x)}{1+a^2 x^2} \, dx}{3 a c} \\ & = -\frac {x \arctan (a x)^2}{a^4 c}+\frac {x^3 \arctan (a x)^2}{3 a^2 c}+\frac {\arctan (a x)^3}{3 a^5 c}-\frac {2 \int x \arctan (a x) \, dx}{3 a^3 c}+\frac {2 \int \frac {x \arctan (a x)}{1+a^2 x^2} \, dx}{3 a^3 c}+\frac {2 \int \frac {x \arctan (a x)}{1+a^2 x^2} \, dx}{a^3 c} \\ & = -\frac {x^2 \arctan (a x)}{3 a^3 c}-\frac {4 i \arctan (a x)^2}{3 a^5 c}-\frac {x \arctan (a x)^2}{a^4 c}+\frac {x^3 \arctan (a x)^2}{3 a^2 c}+\frac {\arctan (a x)^3}{3 a^5 c}-\frac {2 \int \frac {\arctan (a x)}{i-a x} \, dx}{3 a^4 c}-\frac {2 \int \frac {\arctan (a x)}{i-a x} \, dx}{a^4 c}+\frac {\int \frac {x^2}{1+a^2 x^2} \, dx}{3 a^2 c} \\ & = \frac {x}{3 a^4 c}-\frac {x^2 \arctan (a x)}{3 a^3 c}-\frac {4 i \arctan (a x)^2}{3 a^5 c}-\frac {x \arctan (a x)^2}{a^4 c}+\frac {x^3 \arctan (a x)^2}{3 a^2 c}+\frac {\arctan (a x)^3}{3 a^5 c}-\frac {8 \arctan (a x) \log \left (\frac {2}{1+i a x}\right )}{3 a^5 c}-\frac {\int \frac {1}{1+a^2 x^2} \, dx}{3 a^4 c}+\frac {2 \int \frac {\log \left (\frac {2}{1+i a x}\right )}{1+a^2 x^2} \, dx}{3 a^4 c}+\frac {2 \int \frac {\log \left (\frac {2}{1+i a x}\right )}{1+a^2 x^2} \, dx}{a^4 c} \\ & = \frac {x}{3 a^4 c}-\frac {\arctan (a x)}{3 a^5 c}-\frac {x^2 \arctan (a x)}{3 a^3 c}-\frac {4 i \arctan (a x)^2}{3 a^5 c}-\frac {x \arctan (a x)^2}{a^4 c}+\frac {x^3 \arctan (a x)^2}{3 a^2 c}+\frac {\arctan (a x)^3}{3 a^5 c}-\frac {8 \arctan (a x) \log \left (\frac {2}{1+i a x}\right )}{3 a^5 c}-\frac {(2 i) \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+i a x}\right )}{3 a^5 c}-\frac {(2 i) \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+i a x}\right )}{a^5 c} \\ & = \frac {x}{3 a^4 c}-\frac {\arctan (a x)}{3 a^5 c}-\frac {x^2 \arctan (a x)}{3 a^3 c}-\frac {4 i \arctan (a x)^2}{3 a^5 c}-\frac {x \arctan (a x)^2}{a^4 c}+\frac {x^3 \arctan (a x)^2}{3 a^2 c}+\frac {\arctan (a x)^3}{3 a^5 c}-\frac {8 \arctan (a x) \log \left (\frac {2}{1+i a x}\right )}{3 a^5 c}-\frac {4 i \operatorname {PolyLog}\left (2,1-\frac {2}{1+i a x}\right )}{3 a^5 c} \\ \end{align*}
Time = 0.27 (sec) , antiderivative size = 90, normalized size of antiderivative = 0.54 \[ \int \frac {x^4 \arctan (a x)^2}{c+a^2 c x^2} \, dx=\frac {a x+\left (4 i-3 a x+a^3 x^3\right ) \arctan (a x)^2+\arctan (a x)^3-\arctan (a x) \left (1+a^2 x^2+8 \log \left (1+e^{2 i \arctan (a x)}\right )\right )+4 i \operatorname {PolyLog}\left (2,-e^{2 i \arctan (a x)}\right )}{3 a^5 c} \]
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Time = 0.58 (sec) , antiderivative size = 224, normalized size of antiderivative = 1.35
method | result | size |
derivativedivides | \(\frac {\frac {\arctan \left (a x \right )^{2} a^{3} x^{3}}{3 c}-\frac {\arctan \left (a x \right )^{2} a x}{c}+\frac {\arctan \left (a x \right )^{3}}{c}-\frac {2 \left (\frac {a^{2} \arctan \left (a x \right ) x^{2}}{2}-2 \arctan \left (a x \right ) \ln \left (a^{2} x^{2}+1\right )-\frac {a x}{2}+\frac {\arctan \left (a x \right )}{2}-i \left (\ln \left (a x -i\right ) \ln \left (a^{2} x^{2}+1\right )-\operatorname {dilog}\left (-\frac {i \left (a x +i\right )}{2}\right )-\ln \left (a x -i\right ) \ln \left (-\frac {i \left (a x +i\right )}{2}\right )-\frac {\ln \left (a x -i\right )^{2}}{2}\right )+i \left (\ln \left (a x +i\right ) \ln \left (a^{2} x^{2}+1\right )-\operatorname {dilog}\left (\frac {i \left (a x -i\right )}{2}\right )-\ln \left (a x +i\right ) \ln \left (\frac {i \left (a x -i\right )}{2}\right )-\frac {\ln \left (a x +i\right )^{2}}{2}\right )+\arctan \left (a x \right )^{3}\right )}{3 c}}{a^{5}}\) | \(224\) |
default | \(\frac {\frac {\arctan \left (a x \right )^{2} a^{3} x^{3}}{3 c}-\frac {\arctan \left (a x \right )^{2} a x}{c}+\frac {\arctan \left (a x \right )^{3}}{c}-\frac {2 \left (\frac {a^{2} \arctan \left (a x \right ) x^{2}}{2}-2 \arctan \left (a x \right ) \ln \left (a^{2} x^{2}+1\right )-\frac {a x}{2}+\frac {\arctan \left (a x \right )}{2}-i \left (\ln \left (a x -i\right ) \ln \left (a^{2} x^{2}+1\right )-\operatorname {dilog}\left (-\frac {i \left (a x +i\right )}{2}\right )-\ln \left (a x -i\right ) \ln \left (-\frac {i \left (a x +i\right )}{2}\right )-\frac {\ln \left (a x -i\right )^{2}}{2}\right )+i \left (\ln \left (a x +i\right ) \ln \left (a^{2} x^{2}+1\right )-\operatorname {dilog}\left (\frac {i \left (a x -i\right )}{2}\right )-\ln \left (a x +i\right ) \ln \left (\frac {i \left (a x -i\right )}{2}\right )-\frac {\ln \left (a x +i\right )^{2}}{2}\right )+\arctan \left (a x \right )^{3}\right )}{3 c}}{a^{5}}\) | \(224\) |
parts | \(\frac {x^{3} \arctan \left (a x \right )^{2}}{3 a^{2} c}-\frac {x \arctan \left (a x \right )^{2}}{a^{4} c}+\frac {\arctan \left (a x \right )^{3}}{a^{5} c}-\frac {2 \left (\frac {\arctan \left (a x \right )^{3}}{3 a^{5}}+\frac {\frac {a^{2} \arctan \left (a x \right ) x^{2}}{2}-2 \arctan \left (a x \right ) \ln \left (a^{2} x^{2}+1\right )-\frac {a x}{2}+\frac {\arctan \left (a x \right )}{2}-i \left (\ln \left (a x -i\right ) \ln \left (a^{2} x^{2}+1\right )-\operatorname {dilog}\left (-\frac {i \left (a x +i\right )}{2}\right )-\ln \left (a x -i\right ) \ln \left (-\frac {i \left (a x +i\right )}{2}\right )-\frac {\ln \left (a x -i\right )^{2}}{2}\right )+i \left (\ln \left (a x +i\right ) \ln \left (a^{2} x^{2}+1\right )-\operatorname {dilog}\left (\frac {i \left (a x -i\right )}{2}\right )-\ln \left (a x +i\right ) \ln \left (\frac {i \left (a x -i\right )}{2}\right )-\frac {\ln \left (a x +i\right )^{2}}{2}\right )}{3 a^{5}}\right )}{c}\) | \(236\) |
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\[ \int \frac {x^4 \arctan (a x)^2}{c+a^2 c x^2} \, dx=\int { \frac {x^{4} \arctan \left (a x\right )^{2}}{a^{2} c x^{2} + c} \,d x } \]
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\[ \int \frac {x^4 \arctan (a x)^2}{c+a^2 c x^2} \, dx=\frac {\int \frac {x^{4} \operatorname {atan}^{2}{\left (a x \right )}}{a^{2} x^{2} + 1}\, dx}{c} \]
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\[ \int \frac {x^4 \arctan (a x)^2}{c+a^2 c x^2} \, dx=\int { \frac {x^{4} \arctan \left (a x\right )^{2}}{a^{2} c x^{2} + c} \,d x } \]
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\[ \int \frac {x^4 \arctan (a x)^2}{c+a^2 c x^2} \, dx=\int { \frac {x^{4} \arctan \left (a x\right )^{2}}{a^{2} c x^{2} + c} \,d x } \]
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Timed out. \[ \int \frac {x^4 \arctan (a x)^2}{c+a^2 c x^2} \, dx=\int \frac {x^4\,{\mathrm {atan}\left (a\,x\right )}^2}{c\,a^2\,x^2+c} \,d x \]
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